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school_compare/backend/tests/test_benchmarks.py
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"""compute_benchmarks: state-school benchmarks computed from our dataset
(spec §5/§8.6). The disadvantaged average must be weighted by cohort size,
medians must ignore NaN, and only the latest year counts."""
import numpy as np
import pandas as pd
from backend.data_loader import compute_benchmarks
LATEST = 202425
def _df():
rows = [
# Six primary schools, latest year. Disadvantaged RWM chosen so the
# weighted average differs clearly from the unweighted mean:
# weighted = (40*100 + 60*300) / 400 = 55.0 ; unweighted mean = 50.0
dict(year=LATEST, attainment_8_score=np.nan, eligible_pupils=100,
rwm_expected_disadvantaged_pct=40.0, eal_pct=10.0,
sen_support_pct=10.0, disadvantaged_pct=20.0, fsm_pct=15.0, total_pupils=200),
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dict(year=LATEST, attainment_8_score=np.nan, eligible_pupils=300,
rwm_expected_disadvantaged_pct=60.0, eal_pct=20.0,
sen_support_pct=14.0, disadvantaged_pct=24.0, fsm_pct=17.0, total_pupils=280),
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dict(year=LATEST, attainment_8_score=np.nan, eligible_pupils=np.nan,
rwm_expected_disadvantaged_pct=99.0, eal_pct=30.0,
sen_support_pct=18.0, disadvantaged_pct=30.0, fsm_pct=19.0, total_pupils=300),
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dict(year=LATEST, attainment_8_score=np.nan, eligible_pupils=50,
rwm_expected_disadvantaged_pct=np.nan, eal_pct=np.nan,
sen_support_pct=np.nan, disadvantaged_pct=np.nan, fsm_pct=np.nan, total_pupils=np.nan),
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dict(year=LATEST, attainment_8_score=np.nan, eligible_pupils=40,
rwm_expected_disadvantaged_pct=np.nan, eal_pct=40.0,
sen_support_pct=20.0, disadvantaged_pct=40.0, fsm_pct=21.0, total_pupils=350),
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dict(year=LATEST, attainment_8_score=np.nan, eligible_pupils=60,
rwm_expected_disadvantaged_pct=np.nan, eal_pct=50.0,
sen_support_pct=22.0, disadvantaged_pct=44.0, fsm_pct=23.0, total_pupils=400),
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# Two secondary schools (attainment_8 non-null)
dict(year=LATEST, attainment_8_score=45.0, eligible_pupils=180,
rwm_expected_disadvantaged_pct=np.nan, eal_pct=15.0,
sen_support_pct=12.0, disadvantaged_pct=22.0, fsm_pct=12.0, total_pupils=1000),
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dict(year=LATEST, attainment_8_score=50.0, eligible_pupils=200,
rwm_expected_disadvantaged_pct=np.nan, eal_pct=25.0,
sen_support_pct=16.0, disadvantaged_pct=26.0, fsm_pct=14.0, total_pupils=1200),
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# An older-year primary row that must NOT influence anything
dict(year=202324, attainment_8_score=np.nan, eligible_pupils=500,
rwm_expected_disadvantaged_pct=1.0, eal_pct=99.0,
sen_support_pct=99.0, disadvantaged_pct=99.0, fsm_pct=99.0, total_pupils=9999),
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]
return pd.DataFrame(rows)
def test_weighted_disadvantaged_average():
b = compute_benchmarks(_df())
# Row 3 has NaN eligible_pupils and must be excluded from the weighting.
assert b["primary"]["disadvantaged_rwm_expected_pct"] == 55.0
def test_medians_ignore_nan_and_older_years():
b = compute_benchmarks(_df())
assert b["year"] == LATEST
# sen medians over [10,14,18,20,22] = 18 — the only context measure still
# sourced from the performance df (the rest come from the census mart).
assert b["primary"]["sen_support_pct"] == 18.0
# disadvantaged_pct medians over [20,24,30,40,44] = 30
assert b["primary"]["disadvantaged_pct"] == 30.0
def test_benchmarks_use_census_mart_for_context():
census = {
"primary": {"year": LATEST, "fsm_pct": 25.3, "eal_pct": 21.8, "median_pupils": 240},
"secondary": {"year": LATEST, "fsm_pct": 24.1, "eal_pct": 18.9, "median_pupils": 980},
}
b = compute_benchmarks(_df(), census_benchmarks=census)
assert b["primary"]["fsm_pct"] == 25.3
assert b["primary"]["eal_pct"] == 21.8
assert b["secondary"]["eal_pct"] == 18.9
assert b["secondary"]["median_pupils"] == 980
def test_benchmarks_context_none_when_mart_missing():
# The performance df has no fsm_pct and its eal/disadvantaged columns are
# KS2-only — never silently fall back to medianing them for context.
b = compute_benchmarks(_df(), census_benchmarks=None)
assert b["primary"]["fsm_pct"] is None
assert b["primary"]["eal_pct"] is None
assert b["primary"]["median_pupils"] is None
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def test_secondary_block_has_no_disadvantaged_rwm():
b = compute_benchmarks(_df())
assert "disadvantaged_rwm_expected_pct" not in b["secondary"]
# KS2-only columns must not produce a fake secondary disadvantaged anchor
# (the old median over all-through schools' KS2 rows produced 50%).
assert b["secondary"]["disadvantaged_pct"] is None
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def test_provenance_string():
b = compute_benchmarks(_df())
assert b["source"] == "state-school average (computed from our dataset)"
def test_empty_df():
assert compute_benchmarks(pd.DataFrame()) == {}